Question

two resistance 10 ohm and 3 ohm are connected in parallel across a battery if there is a current of 0.2 m in the 10 ohm resistance the EMF of the battery will be​

Answer 1

Answer:

2 volt

Explanation:

We know that in the parallel connection voltage is same in both resistance.

hence v = i*r

v = 0.2*10

= 2 volt

Answer 2

The EMF and current supplied by the battery is 2 V and 0.87 ampere respectively.

Given,

Resistors that are in parallel=10 ohm and 3 ohm

Current in 10 ohm resistor=0.2 ampere.

To find,

the EMF of the battery.

Solution:

• When resistors form a parallel combination, the equivalent resistance comes to be as per the following expression:
• $\frac{1}{Rnet} =\frac{1}{R1} +\frac{1}{R2}$.
• When resistors form a series combination, the equivalent resistance comes to be as per the following expression:
• $Rnet=R1+R2$.
• Voltage supplied by the battery is same in each resistor when the resistors are in a parallel combination. Its the current that gets divided.
• Current supplied by the battery is same in each resistor when the resistors are in a parallel combination. Its the voltaget that gets divided.

The voltage(emf) supplied by the battery is equal to the voltage in 3 ohm resistor and that in 10 ohm resistor.

The voltage in 10 ohm resistor will be:

V=IR

V=0.2 x 10

V=2 V.

The same voltage will be in 3 ohm resistor.

The current in 3 ohm resistor will be:

V=IR

I=V/R

I=2/3

I=0.67 ampere.

The current supplied by the battery will be:

I=(0.2+0.67)

I=0.87 ampere.

Thus, the EMF of the battery is 2 V.

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