Question

Two resistance 10ohm and 40ohm are connected i I parall in a circuit of 12v battery then what will be the equivalent resistance of the circuit ?find the heat evolve if the circuit runs for 30minutes.

Answer 1

Answer:

The answer is 8 ohm and 259.2 Kj

Step-by-step explanation:

The total resistance in parallel combination is 8 ohm( given in dig. )

Heat evolved: V^2R/T

(12×12)/8×30×60

=259200J

=259.2Kj

Answer 2

The equivalent resistance of the circuit=8 ohm

The heat evolved =32.4 KJ

Step-by-step explanation:

Let $R_1=10\Omega$

$R_2=40\Omega$

Potential difference=V=12 V

When the resistance are connected in parallel then

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}$

Using the formula

$\frac{1}{R_{eq}}=\frac{1}{10}+\frac{1}{40}$

$\frac{1}{R_{eq}}=\frac{4+1}{40}$

$\frac{1}{R_{eq}}=\frac{5}{40}=\frac{1}{8}$

$R_{eq}=8\Omega$

Time=30 minutes=$30\times 60=1800s$

1 minute=60 s

Current,I=$\frac{V}{R}$

Using the formula

$I=\frac{12}{8}=\frac{3}{2}=1.5 A$

Heat=$I^2Rt$

Where I=Current

R=Resistance

t=Time

Using the formula

Heat, E=$(1.5)^2\times 8\times 1800=32400J$

Heat, E=$\frac{32400}{1000}=32.4 KJ$

1 KJ=1000 J

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