Two resistance 122 and 22 are connected in
series and then in parallel. The ratio of the
effective resistance of series and parallel
combination of resistances is
(A)9:2
(B) 2:9
(C) 1:2
(D) 3:1
Answers
Answered by
0
Step-by-step explanation:
when resistance are connected in series
R= r1+r2
= 122+22= 144ohm
when resistance are connected in parallel
1/R= 1/r1+1/r2
= 1/122+1/22
= 144/2684
1/R= 144/2684
R= 2684/144
ratio of resistance
144:2684/144
= 144:2684/144
= 20736: 2684
= 9:2
Similar questions
Computer Science,
2 months ago
Math,
2 months ago
Accountancy,
2 months ago
English,
4 months ago
English,
4 months ago
Chemistry,
10 months ago
Math,
10 months ago