Question

two resistance are connected in (a) series (B) parallel the equivalent resistance in the two cases are 9 and 2 ohm respectively then find the resistance of its component resistor​

Answer 1

In series the equivalent resistance is equal to the sun of the resistances

Therefore, In Series = 9+2= 11 ohm

In parallel the equivalent resistance is calculated by formula

1/req=(1/r1)+(1/r2)

=(1/9)+(1/2)

=(2+9)/18

=11/18

Therefore req= 18/11