Physics, asked by maths4995, 1 year ago

two resistance are of same material and are having same length if the ratio of their cross sectional area is 2:11 then what will be the ratio of their resistance ​

Answers

Answered by amandon1111
18
The resistance being inversely proportional to the cross sectional area,has the ratio for two resistors with given ratio of cross sectional areas in the opposite order. So it becomes 11:2.Ans..

I have written it by myself please mark it as the brainllist if it will help you please say thanks for this answer too. . .

maths4995: please explain
maths4995: explain
Potenz: R= Rho l/r....Given the ratio of
area of cross section of both the resistances as 2:11, ratio of r1 to r2= rho l/A1÷ rho l/A2(rho cancels off)= l/2÷l/11 (l cancels off) therefore the resulting ratio of the resistances= R1:R2=11:2
Potenz: Hope it helps!
maths4995: thank you very much
Potenz: It's okay!
Answered by koshalyaswami
0

Explanation:

let-

Resistance 1

Length =L

Resistivity =p p=ohm meter

Area of cross section=2A

Resistance 2

Length =l

Resistivity =P

area of cross section=11A

whe have to find the ratio between their Resistance

so,

p L

2A

r = P l

11A

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