Question

Two resistance ate joined parallel whose resultant is 6/5ohm one of resistance wire is broken and effective resistance becomes 2ohm then resistance of wire that got broken was???

Answer 1

It is simple....
If the resistances are connected in parallel they give total resistance as the sum of their reciprocals ......
So 1/R1 + 1/R2 = 1/Rp
Which gives
$\frac{1}{2} + \frac{1}{r2} = \frac{5}{6} \\ \frac{1}{r2} = \frac{5}{6} - \frac{1}{2} \\ \frac{1}{r2} = \frac{5 - 3}{6} \\ \frac{1}{r2} = \frac{2}{6} \\ \frac{1}{r2} = \frac{1}{3} \\ r2 = 3$
So r2 = 3 ohm is the right answer ....
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