Two resistance of 3 ohm and 6 ohm are connected in parallel. This combination is connected in series with a resistance of 8 ohm. If supply voltage is 100 v , determine :
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The effective resistance of parallel combination is (3×6)/9 = 2ohm
The effective resistance of whole circuit
→ 2 + 8 ohm ( As the r in series)
→ 10 ohm
Now V = 100V R = 10 ohm
So
I = V/R
I = 100/10
I = 10A
The effective resistance of whole circuit
→ 2 + 8 ohm ( As the r in series)
→ 10 ohm
Now V = 100V R = 10 ohm
So
I = V/R
I = 100/10
I = 10A
laba46:
Wrong dear brother.
Answered by
1
Hope it is the amount of current.
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