two resistance of 4 ohm and 2 ohm with a battery are connected in series. find out the current flowinɡ throuɡh the circuit and the total resistance of the circuit .
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as given question there are two Omega resistors R1 is equal to 4 ohm and add to is to with batteries connected in series find out the current flowing and the total resistance in the circuit so resistance is not dependent on the current so whatever the current will be flowing will be flowing in series also like in the parallel.
I I LET IT BE THE CURRENT THEN I WILL BE THE CURRENT FLOWING IN THE RESISTOR WITH TOTAL RESISTANCE 6 OHM
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incomplete question voltage of battery not given by you
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