Question

Two resistance of 6 ohm each are connected in parallel with third
resistance of 3 ohm in series the equivalent resistance will be:
3 ohm
4 ohm
6 ohm
None​

Answer 1

Answer:

the equivalent resistence will be

1/Rp = 1/6 + 1/6

= 2/6

Rp = 3

Rs = 3 + 3

= 6 ohm

Explanation:

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Answer 2

Answer:

The equivalent resistance in the circuit is 6 Ω.

Explanation:

Resistors in the circuit = 6 Ω and 6 Ω in parallel and 3 Ω in series.

• $\sf{R_1}$ = 6 Ω
• $\sf{R_2}$ = 6 Ω
• $\sf{R_3}$ = 3 Ω

Equivalent resistance =

$\bigstar \: \boxed{\sf{ \frac{1}{R_P} = \frac{1}{R_1} + \frac{1}{R_2}}}$

$\longrightarrow \: {\sf{ \dfrac{1}{R_P} = \dfrac{1}{6} + \dfrac{1}{6}}}$

$\longrightarrow \: {\sf{ \dfrac{1}{R_P} = \dfrac{2}{6}}}$

$\longrightarrow \: {\sf{R_P} = \dfrac{6}{2} = 3}$

$\sf{R_P}$ = 3 Ω

$\sf{R_P}$ and $\sf{R_3}$ are in series.

$\bigstar \: \boxed{\sf{R_s = R_P +R_3 }}$

$\longrightarrow \: {\sf{R_s = 3 +3}}$

$\longrightarrow \: {\sf{R_s = 6}}$

Therefore, the equivalent resistance in the circuit is 6 Ω.