Question

Two resistance of 62 each are connected in parallel with third
resistance of 322 in series the equivalent resistance will be:
322
492
692
None
*

Answer 1

Answer:

answer is 692

Explanation:

Answer 2

Answer:

The equivalent resistance in the circuit is 353 Ω. (Option none)

Explanation:

Resistors in the circuit = 62 Ω and 62 Ω in parallel and 322 Ω in series.

• $\sf{R_1}$ = 62 Ω
• $\sf{R_2}$ = 62 Ω
• $\sf{R_3}$ = 322 Ω

Equivalent resistance =

$\bigstar \: \boxed{\sf{ \frac{1}{R_P} = \frac{1}{R_1} + \frac{1}{R_2}}}$

$\longrightarrow \: {\sf{ \dfrac{1}{R_P} = \dfrac{1}{62} + \dfrac{1}{62}}}$

$\longrightarrow \: {\sf{ \dfrac{1}{R_P} = \dfrac{2}{62}}}$

$\longrightarrow \: {\sf{R_P} = \dfrac{62}{2} = 31}$

$\sf{R_P}$ = 31 Ω

$\sf{R_P}$ and $\sf{R_3}$ are in series.

$\bigstar \: \boxed{\sf{R_s = R_P +R_3 }}$

$\longrightarrow \: {\sf{R_s = 31 +322}}$

$\longrightarrow \: {\sf{R_s = 353}}$

Therefore, the equivalent resistance in the circuit is 353 Ω.