two resistance of equal value when connected in parallel given in equivalent resistance of R if these registers are connected in series the equivalent resistance will be
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so let's consider the value of each resistor to be 'r'
we have been given that :
1/R = 1/r + 1/r
1/R = 2/r
r = 2/R
so if we connect the resistors in series we get
(let's denote equivalent resistance in series as R1)
R1 = r + r
R1 = 2/R + 2/R
R1 = 4/R
so the resistance when connected in series will be 4 divided by their resistance in parallel.
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