Question

two resistance R and 2R are connected in parallel in an electric circuit. the thermal energy developed in R and 2R are in ratio

Answer 1

Assume current I is flowing on the circuit ... Then find the current drop across each resistor and use joules law of heating that is (I^2)R ... But the values get the answer

Answer 2

Thermal energy = V²t/R

In parellel arrangement V is constant

So, for a time t
Thermal energy ∝ 1/R

Ratio of their thermal energy = R₂ : R₁ = 2R : R = 2 : 1