Question

Two resistance R1 = 100+_3 ohm and R2= 200+_4 ohm are connected in series.what is their equivalent resistance and find its % error
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Answer 1

Given :

Two resistances

• R₁ = (100 ± 3) Ω
• R₂ = (200 ± 4) Ω

are connected in series.

To Find :

Equivalent resistance and percentage error in the measurement$.$

Solution :

❖ The equivalent resistance of series combination is

➙ R = R₁ + R₂

➙ R = 100 + 200

➙ R = 300 Ω

The error in equivalent resistance is given by

➙ ∆R = ∆R₁ + ∆R₂

➙ ∆R = 3 + 4

➙ ∆R = 7 Ω

Percentage error in measurement of resistance is given by

➙ % Error = ∆R/R × 100

➙ % Error = 7/300 × 100

➙ % Error = 7/3

➙ % Error = 2.33%

Knowledge BoosteR :

• Least count errors are random errors but within a limited size; they occur with both random and systematic errors.
• In all mathematical operations, the errors are of addictive nature.