Question

Two resistance R1=(16+-.3)ohm and R2=(48+-.5) ohm are connecting in parallel. Find the total resistance of the composition.
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Answer 1

Answer:

Let r be the total resistance of the composition

Since resistances are put in parallel, the formula is

1/r=1/R1 + 1/DE

1/r=1/16+1/48 =4/48= 1/12

Therefore r = 12Ans