Physics, asked by harshdeepsinghsaini4, 9 months ago

Two resistance r1 = (40 + 0.4)2 and r2 = (20 + 0.8)2 are connected in parallel. Find the total resistance with limits of percentage error.

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Answered by Anonymous
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Two resistance r1 = (40 + 0.4)2 and r2 = (20 + 0.8)2 are connected in parallel. Find the total resistance with limits of percentageTwo resistance r1 = (40 + 0.4)2 and r2 = (20 + 0.8)2 are connected in parallel. Find the total resistance with limits of percentageTwo resistance r1 = (40 + 0.4)2 and r2 = (20 + 0.8)2 are connected in parallel. Find the total resistance with limits of percentageTwo resistance r1 = (40 + 0.4)2 and r2 = (20 + 0.8)2 are connected in parallel. Find the total resistance with limits of percentage. .

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