Two resistance r1 = (40 + 0.4)2 and r2 = (20 + 0.8)2 are connected in parallel. Find the total resistance with limits of percentage error.
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Secondary School Physics 5 points
If two resistors of resistance R1=(4 ± 0.5)ohm and R2=(16 ± 0.5)ohm are connected (1) In series and (2) Parallel . Find the equivalent resistance in each case with limits of % error.
Ask for details Follow Report by TauseefSehar 02.10.2018
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Hey there!
Two resistors (R1 & R2) are connected in parallel.
We know,
1/re = 1/r₁ + 1/r₂
Then re = r₁r₂/r₁+r₂
Putting values:
=50×100/50+100
=5000/160
=100/3 ← Ans
Now, Parallel Connection error:
= R1^2 dB +R2^2dA/ (R1+R2)^2
=50×50 (3)+100×100 (2)/150×150
=7500+20000/150×150
=11/9 ← (Ans)
Relative Error =
=(11/9)/100/3
=0.03666 ←(Ans