Question

Two resistance r1=(5+0.2)ohm and r2 =) 10+6.1 ohm are connected in parallel. Find the value of equivalent resistance with limits of % error​

Answer 1

Explanation:

Solution -

Percentage error in equivalent resistance for resistors connected in parallel is given by -

∆r/R % = ∆r1/R1 % + ∆r2/R2 %

∆r/R % = 0.2/5 × 100 + 0.1/10 × 100

∆r/R % = 4 + 1

∆r/R % = 5 %

Therefore, Percentage