Question

Two resistance R1 = (50+ - 0.2) and R2=( 75+ - 0.5)N are connected in series. Find the total resistance of
the combination and maximum percentage error in the total resistance.​

Answer 1

Explanation:

R1=(50.0+-0.2)

= 50.0-0.2

= 49.8 ohm

R2=(75.0+-0.5)

=75.0-0.5

=74.5 ohm

NET RESISTANCE= R1+R2

=49.8+74.5

=124.3 ohm

Hope this helps you