Two resistance10ohmand20ohmare connected in parallel A battery supplies 6A Of current to the combination calculate the current in each resistor
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R1 = 10ohm
R2 = 20 ohm
Equivalent resistance = 1/R1 + 1/ R2
=> 20/3 ohm
I = 6A
V = IR
V => 6 × 20/3 => 40V
Now, we know potential difference remains the same in parallel arrangement of resistances.
So,
Current through R1 = V/R1 => 40/10 = 4A
Current through R2 = V/R2 => 40/20 = 2A
Cheers!
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