Physics, asked by renumittalia5551, 11 months ago

Two resistances 2, 4 are connected in parallel the ratio of current passing through them when a potential difference is applied across the ends

Answers

Answered by KhanLuqman
3

Answer:

Ratio of current passing through them

= 2 : 1

Explanation:

As both resistors are connected in parallel thus the potential difference across each is same = V

Resistance of first resistor = R1 = 2 ohm

Resistance of second resistor = R2 = 4 ohm

We know that V = IR => I = V/R

THUS the current passing through R1

= I1 = V/2

similarly I2 = V/4

HENCE

 \frac{l1}{l2}  =  \frac{v}{2}  \div  \frac{v}{4}  =  \frac{v}{2}  \times  \frac{4}{v}  =  \frac{4}{2}  =  \frac{2}{1}

=> I1 : I2 = 2 : 1

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