Two resistances 30 and 60, connected in the left and the right gap of Wheatstone’s network. If the length of
the wire used is 120cm, then the find the distance of the null point from the centre of the wire.
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★ According to principle of meter bridge
R1/x = R2/(L-x)..........(1)
where L = length of wire
x = null point from R1
(L-x) = null point from R2
now,
substitute the values in eqn.
30/x = 60/(120-x)
=> x = 4cm (null point from R1 is 4cm)
Center of wire = 120/2=60cm
therefore, null point from Center of wire = 60-4=56cm
happy to help
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