Question

Two resistances 4 ohms and 2 ohms, are
connected in series a 3 volt battery is con-
nected as show in the figure. Find the cur-
rent flowing through the circuit.​

Answer 1

Answer:

R=(4+2)ohm

R=6ohm

by ohm's law

V=RI

I=V/R

I=3/6

I=1/3

I=0.333amp

Answer 2

Answer:

Rs = R1 + R2

Rs = 4 + 2

Rs = 6ohm

Now, We know

V = IR

I = V/R

I = 3/6

I = 2

Therefore, The Current Flowing through the circuit is 2A (amp)