Question

Two resistances are connected in series as shown in the diagram.
(1) What is the current through the 5 ohm resistance ?
(ii) What is the current through R?
(mm) What is the value of R?
(iv) What is the value of V?
I​

Answer 1

Explanation:

$i = \frac{v}{r}$

therefore I=

$\frac{10}{5} = 2 \: a$

AS THE CURRENT FLOWING THROUGH THE CIRCUIT IS SAME

R=V/I

THEREFORE R=6/2=3 ohm

Vt=V1+V2

Vt=10+6

Vt=16 V

Answer 2

Explanation:

Given Two resistances are connected in series as shown in the diagram.(1) What is the current through the 5 ohm resistance

(ii) What is the current through R?

(mm) What is the value of R?

(iv) What is the value of V?  

• So two resistances are connected in series. We need to find
• Current through 5 ohm resistor  (R = 5 ohm)
• So voltage is 10 V across 5 ohm resistor
•        V = 10 V
• Now current I = V/R
•                          = 10 / 5
•                   I = 2 Amps
• In the circuit 5 ohm and Resistance R are in series. So we get current through the resistance as same
• So the current through R is I = 2 Amps.
• So value of V is 6 Volts.
• Therefore R = V/I
•                      = 6/2
•                   R = 3 ohms

Reference link will be

https://brainly.in/question/26925842