Question

Two resistances are of 4 ohm and 12 ohm. How much current will flow in the circuit on them with a cell of 10 volt, if resistances are connected (i) in series, (ii) parallel arrangements ?​

Answer 1

Answer:

1) In series

Req = R1 + R2 = 4 + 12 = 16 ohm

I = V / R = 10 / 16 = 5/ 8 = 0.625 A

2 ) In parallel

Req = R1R2/ R1 + R2

= 12 x 4 / 16= 3 ohm

I = V / R = 10 / 3 = 3.333 A