Question

Two resistances connected in parallel across a 100 V supply, draws 9 A current. If power dissipation in one resistor is 500 W. The resistance of other resistor is
option
A : 100ohm
B:. 75ohm
C: 50ohm
D: 25ohm​

Answer 1

Answer:

if you know th diagram

Explanation:

In our to find out the current drawn when R1 and R2 will be in series with V2, our aim to find the value of R1 and R2.

Voltage across both the resistor is 100V (since they are parallel to V2)

Power through one of them say R1 is 600W

P1 = (V*V)/R1

R1 = (100*100)/600 = 16.667 ohms

Net power from source is, P = V*I = 100*10 = 1000W

Power disipated in R1 is P1 = 600W

So, power dissipated through R2 is, P2 = 1000W - 600W = 400W

Again, for R2, P2 = (V*V)/R2

R2 = (100*100)/400 = 25 ohms