Two resistances of 25 ohm and 15 ohm are combined first in series with each other and then in parallel with 40 ohm.The combined will be
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Connected in series = 25+30 =40 ...and then arranged in parallel with 40 ohms....so 1/R= 1/40+1/40=2/40.....so, R=40/2 = 20 ohms is the effective resistance of the combination.
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Explanation:
Connected in series = 25+30 =40 and
then arranged in parallel with 40 ohms
so 1/R= 1/40+1/40=2/40.
so, R=40/2 = 20
therefore 20 ohms is the effective resistance of the combination.
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