Question

two resistances of 3 Ω and 6 Ω are connected in parallel to a 6 V battery. What would be the current flowing through the circuit



please reply fast..

Answer 1

Answer:

Here is your Answer

Explanation:

Req= (R1*R2)/(R1+R2)

=(3*2)/(3+2)

=6/5

=1.2 Ohms

I= V/Req

=6/1.2

= 5 Amps.