Question

two resistances of 30 and 70 ohms are connected in series and pd of 100v applied across the whole arrangement calculate the pd registered by a voltmeter of resistance 30 k ohm when placed across the longer resistance
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Answer 1

Answer:

Correct option is

C

40 V

Components connected in series are connected along a single path, so the same current flows through all of the components. The current through each of the components is the same, and the voltage across the circuit is the sum of the voltages across each component.

Components connected in parallel are connected so the same voltage is applied to each component. In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents through each component.

In the given circuit, the voltmeter with a resistance of 600 ohms and the 300 ohms resistor are connected in parallel. So the combined resistance is

300

1

+

600

1

=

0.005

1

=200ohms.

Now the resistances 200 ohms, 100 ohms and the combined resistance of 200 ohms are all connected in series. So the total resistance is 200+100+200 = 500 ohms.

Now, the current through the circuit is calculated as I=V/R = 100/500 = 0.2 A.

The voltmeter of 600 ohms is connected across the 300 ohms resistance.

Hence, the voltmeter reading would be V=IR = 0.2×200=40V

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