Question

Two resistances of 4 ohm and 8 ohm are connected in parallel . What would be the combined resistance of the system

Answer 1

$\huge{\sf{Given}}$

Two resistors are connected in parallel

R₁ = 4Ω

R₂ = 8Ω

$\huge{\sf{To \: find}}$

Equivalent resistance,

Solution

● Then equivalent resistance of a parallel combination is given by, 1/Rₙₑₜ = 1/R₁ + 1/R₂ ... + 1/Rₙ

✭ Equivalent Resistance :

→ 1/Rₙₑₜ = 1/R₁ + 1/R₂ ... + 1/Rₙ

R₁ = 4Ω

R₂ = 8Ω

→ 1/Rₙₑₜ = 1/4 + 1/8

→ 1/Rₙₑₜ = (1/4 × 2/2) + 1/8

→ 1/Rₙₑₜ = 2/8 + 1/8

→ 1/Rₙₑₜ = (2+1)/8

→ 1/Rₙₑₜ = 3/8

→ Rₙₑₜ = 8/3

→ Rₙₑₜ = 2.7 Ω

$\huge\pink{Hope\:it\:helps\:you}$

Answer 2

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