Two resistances of when connected in parallel give resultant value of 2 Ohms; when connected in series the value become 9 ohms. calculate the value of each resistance
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Hello
Let the resistances be r1 and r2
The given equivalent resistances are
For parallel = 2 ohm
For series = 9 ohms
So, from ohms law
The speed resistance will be
R(eq) = r1 +r2
Or,
r1 + r2 = 9 ohms
Now
For parallel connection

Now
R1 = 18/r2
And
R1 = 9 - r2
So,
Equating both

Now
equating with Zeroes we get the value of x as 6 and 3
So,
Now ,
From equation 1
R1+R2 =9
Of R2 =6 then R1 will be 3
And if R2 =3 then R1 will be 6
So ,
The value of the two resistances is equal to
6 ohm and 3 ohm
Hope this will be helping you ✌️
Let the resistances be r1 and r2
The given equivalent resistances are
For parallel = 2 ohm
For series = 9 ohms
So, from ohms law
The speed resistance will be
R(eq) = r1 +r2
Or,
r1 + r2 = 9 ohms
Now
For parallel connection
Now
R1 = 18/r2
And
R1 = 9 - r2
So,
Equating both
Now
equating with Zeroes we get the value of x as 6 and 3
So,
Now ,
From equation 1
R1+R2 =9
Of R2 =6 then R1 will be 3
And if R2 =3 then R1 will be 6
So ,
The value of the two resistances is equal to
6 ohm and 3 ohm
Hope this will be helping you ✌️
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