Question

Two resistances R1=(100±3) lamuda R2=(150±2)lamuda,are connected in series. What is their equivalent resistance?

Answer 1

Explanation:

ANSWER

R

1

=100±3w

R

2

=200±μw

Equivalent resistance is series R=R

1

+R

2

=300

Error ΔR=ΔR

1

+ΔR

2

=4+3

=7

Equivalent resistance with error =300±7ω

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Answer 2

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Question

Two resistances R1=(100±3) lamuda R2=(150±2)lamuda,are connected in series. What is their equivalent resistance?

$\huge{\underline{\underline {\mathtt{\purple{A}\pink{N}\green{S}\blue{W}\red{E}\orange{R}}}}}$

$\Large\fbox\purple{R = (250 ± 5)Ω}$

Solution

R1 = 100 ± 3Ω

R2 = 150 ± 2Ω

To find : Equivalent resistance

Let equivalent resistance be R, = ?

R = R1 + R2

= (100 ± 3) + (150 ± 2)

= (100 + 150) (3 + 2)

= (3 + 2) + (250)

R = (250 ± 5)Ω

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