Two resistances R1 = (100 ± 3) Ω, R2 = (150 ± 2) Ω, are connected in series. What is their equivalent resistance?
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Answer:
(250 ± 5) Ω
Explanation:
Given :
R₁ = (100 ± 3) Ω
R₂ = (150 ± 2) Ω
To find :
The equivalent resistance in series
Formula :
If R₁ and R₂ are connected in series, R eq = R₁ + R₂
Error should always be added
Solution :
R eq = 100 + 150 = 250
Error = 2 + 3 = 5
Hence, the equivalent resistance = (250 ± 5) Ω
Hope it helps!
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