Question

Two resistances R1 =( 3_+ 0.2 ) ohm and R2 =( 2 _+ 0.3) ohm are connected in series . Find the error in the Total Resistance.​

Answer 1

Answer:

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Explanation:

Let R is the equivalent resistance for parallel combination and ΔR is the error(in its measurement respective to the error in the values of resistors)

Hence,

R

1

=

R

1

1

+

R

1

R

1

=

R

1

+R

2

R

1

R

2

R=

3+6

3×6

∴R=2Ω

Now,

R

2

ΔR

=

(R

1

)

2

ΔR

1

+

(R

2

)

2

ΔR

2

R

2

ΔR

=

(3)

2

0.1

+

(6)

2

0.5

R

2

ΔR

=

4

0.1

ΔR=0.1

Hence the resistance of the combination is

R=(2.00±0.1)Ω

Answer 2

Answer:

the answer is 3.2+2.3 equal to 5.5