Question

Two resistances R1 and R2, when connected seperately to the same potential differences, it was seen that the current flowing through R1 was six times the current flowing through R2. Determine the ratio of R1 and R2

Answer 1

Answer:

$\frac{R₁}{R₂} = \frac{1}{6}$

Explanation:

Let I₁ and I₂ be the current flowing through the circuit when connected seperately to potential difference say V.

I₁ = 6I₂ ......................(1)

By Ohm's Law

V = I₁R₁ and V = I₂R₂

or I₁R₁ =I₂R₂

or 6I₂R₁ =I₂R₂

or 6R₁ = R₂

$\frac{R₁}{R₂} = \frac{1}{6}$

Answer 2

Answer:

\frac{R₁}{R₂} = \frac{1}{6}R₂R₁=61

Explanation:

Let I₁ and I₂ be the current flowing through the circuit when connected seperately to potential difference say V.

I₁ = 6I₂ ......................(1)

By Ohm's Law

V = I₁R₁ and V = I₂R₂

or I₁R₁ =I₂R₂

or 6I₂R₁ =I₂R₂

or 6R₁ = R₂

\frac{R₁}{R₂} = \frac{1}{6}R₂R₁=61