Question

Two resistances when connected in parallel
give resultant value of 2 , when connected
in series the value becomes 9 2. Calculate
the value of each resistance.​

Answer 1

Answer:

Explanation:

Here is the answer

Answer 2

Hope this helps

Explanation:

R 1 + R 2 = 92 Ohm (series)   ------------(1)

1 /R1 + 1 /R2 = 1/R

R = R1 x R2/ R1 + R2 = 2 Ohm (parallel)

R1 x R2 = 184 Ohm

$[R1 - R2 ]^{2} = [R1 + R2]^{2} - 4. R1. R2$

                 = $92^{2}$ - 4 x 184

                 = 8464 - 736

                 = 7728

{R1 - R2}     = 88 -----------------(2)

Solving (1) and (2)

R1 = 90 Ohm

R2 = 2 Ohm