Question

Two resistances when connected in parallel give resultant value of 2 ohm, when connectedin series the value becomes 9 ohm. Calculate the value of each resistance.

Answer 1

Answer:

Explanation:

LET THE EACH RESISTORS BE R1 AND R2

CONDITION 1: CONNECTED IN PARALLEL

1/R NET = 1/ R1+ 1/ R2

R NET = R1*R2/( R1+R2)

2=R1*R2/(R1+R2)................................(1)

CONDITION 2: CONNECTED IN SERIES

R NET = R1+R2

9 = R1 +R2.................................(2)

SUBSTITUTING (2) IN(1)

2= R1*R2/9

R1*R2= 18

THERE FORE THE TWO NUMBERS MUST SATISFY THE CONDITION

[A]SUM MUST BE EQUAL TO 9

[B]PRODUCT MUST BE EQUAL TO 18

THEREFORE THE RESISTORS ARE:

R1= 6 OHMS

R2= 3 OHMS.

HOPE THIS HELPS.