Two resistances when connected in parallel give resultant value of 2 ohm;when connected in series the value becomes 9 ohms. calculate the value of each resistance.
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R series=9
R1+R2 =9
Rp=1/2
(1/R1)+(1/R2)
Solve all this and u will get the answer
R1= 6 and R2=3
Hope this helps
R1+R2 =9
Rp=1/2
(1/R1)+(1/R2)
Solve all this and u will get the answer
R1= 6 and R2=3
Hope this helps
Satwika4:
Hey...may i know if my answer is helpful??
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