Question

Two resistances when connected in series, their resultant resistance is 10 Ohm, but when they are connected in parallel their resistance is 2.4Ohm. Find the value of each resistance separately.

Answer 1

Answer:

i don't know

Explanation:

i don't understand

Answer 2

Answer:

Given R

S

​

=10Ω;R

P

​

=2.4Ω;R

1

​

=?;R

2

​

=?

Solution:

Effective resistance when connected in series and parallel.

R

S

​

=R

1

​

+R

2

​

=10             ............(1)

R

P

​

1

​

=

R

1

​

1

​

+

R

2

​

1

​

=

R

1

​

R

2

​

R

1

​

+R

2

​

​

∴R

P

​

=

R

1

​

+R

2

​

R

1

​

R

2

​

​

=2.4             ............(2)

From egn (1) and (2)

10

R

1

​

R

2

​

​

=2.4

⇒R

1

​

R

2

​

=24

∴R

2

​

=

R

1

​

24

​

Substituting R

2

​

 in eqn (1)

R

1

​

+

R

1

​

24

​

=10;R

1

2

​

+24=10R

1

​

R

1

2

​

−10R

1

​

+24=0

(R

1

​

−6)(R

1

​

−4)=0

∴R

1

​

=6Ω or R

1

​

=4Ω

R

2

​

=

6

24

​

 or R

2

​

=

4

24

​

=4Ω. or =6Ω

R

1

​

=6Ω,R

2

​

=4Ω.

Explanation:

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