Question

two resistences R₁ and R₂ have effective resistence Rₓ when connected in series combination and Rₐ when connected in parallel combination RₓRₐ=16 and R₁/R₂=4 the values of R₁ and R₂ are-

Answer 1

Step-by-step explanation:

Rx= R1*R2/R1+R2

Ra= R1+R2

then

Rx*Ra= R1*R2=16. (1)

and R1/R2= 4 given

R1= 4R2 put in eqn (1)

4R2^2=16

R2=2ohm

R1=8ohm