Question

Two resister having resistance of 16 ohm to and 14 ohm are connected in series if a potential difference of 18V is applied across them calculate the potential difference across the end of each individual resistor

Answer 1

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Answer 2

Question

Two resistor having resistances of 16 ohm and 14 ohm are connected in series if a potential difference of 18 V is applied across them calculate the potential difference across the end of each individual resistor

Given

$\sf \: R_{1} = 16 \: and \: \: R_{2} = 14 \\ \sf R_{s} = 14 + 16 = 30$

Required to Find

Calculate the potential difference across the end of each individual resistor.

Solution

Let the current flowing through the circuit be I and the potential difference across the end 16.

$\sf \:a nd \: 14 \: be \: V_{1} \: and \: V_{2} \: respectively.$

$\sf \: V = I R \\ \\ \sf \: V \: = V_{1} + V_{2} = 18V \\ \\ \sf \: I = \dfrac{V}{R} \\ \\ = \sf \: \frac{18 \: V}{30}$

I = 0.6 A.

$\sf \: V_{1} = IR_{1} \\ \\ \sf V_{1} = 0.6 \times 16 = 9.6V \\ \\ \sf \: V_{2} \: \: IR_{2} = 0.6 \times 14 = 8.4V$

Therefore, the current flowing in the circuit is 0.6 A and the potential differences across the end of the resistances 16 and 14 are 9.6 V and 8.4 V respectively