Question

TWO RESISTERS ARE CONNECTED IN PARALLEL. 5ohm, 20ohm,
Find the effective resistance of the circuit?
Calculate current in the circuit​

Answer 1

Explanation:

Answer:-

Given that:-

• Two resistors are connected in parallel.
• The values are 20 ohm and 5 ohm.

To find:-

• Effective resistance
• Current in the circuit.

Let's Do!

We know that for parallel combinations:-

$\rm{\dfrac{1}{R_e} = \dfrac{1}{R_1} + \dfrac{1}{R_2}}$

• Where Re is the equivalent resistance
• Where R1 is one resistance
• And R2 is the other one

$\rm{\dfrac{1}{R_e} = \dfrac{1}{20} + \dfrac{1}{5}}$

$\rm{\dfrac{1}{R_e} = \dfrac{1 + 4}{20}}$

$\rm{\dfrac{1}{R_e} = \dfrac{5}{20}}$

$\rm{R_e= 4 \ \Omega }$

2nd Question:-

To calculate current, we need voltage which is not given. Data insufficient.

However , V = IR

• Where V is voltage
• Where I is current

• Where R is resistance.

Answer 2

To Find:-

• Find the effective resistance of the circuit?
• Current in the circuit.

Given:-

• Two resisters are connected in parallel.
• Values are 5ohm , 20 ohm.

As We know that:-

$\rm{\dfrac{1}{ \: R_e} = \dfrac{1}{R_1} \: + \: \dfrac{1}{ \:R_2\: } }$

Solution:-

$\rm{\dfrac{1}{ \: R_e} = \dfrac{1}{20} \: + \: \dfrac{1}{ \: 5 \: } }$

$\rm{\dfrac{1}{ \: R_e} = \dfrac{1}{20} \: + \: \dfrac{1}{ \: 5 \: } \times \: \dfrac{4}{4} }$

$\rm{\dfrac{1}{ \: R_e} = \dfrac{1}{20} \: + \: \dfrac{4}{ \: 20 \: } }$

$\rm{\dfrac{1}{ \: R_e} = \dfrac{5}{20} }$

$\rm{\dfrac{1}{ \: \: R_e} = \: 5\Omega }$

2.

To calculate the current , we need the value of voltage but it's not given so the data is insufficient.

Extra Information:-

• SI unit of charge is Coulombs.

• SI unit of work is Joule.

• 1000 Joule = 1 kiloJoule.