Question

Two resisters R1= (8+- 0.4)
ohm and R2 = (6+- 0.3) ohm
are connected in series .
Determine the effective
resistance in series, within
the error limit​

Answer 1

Answer:

When the two resistors are connected in parallel, the equivalent resistance will be

R

P

=

R

1

+R

2

R

1

R

2

Differentiating both sides ,

R

P

ΔR

P

=

R

1

ΔR

1

+

R

2

ΔR

2

+

R

1

+R

2

Δ(R

1

+R

2

)

R

P

ΔR

P

=

6

0.3

+

10

0.2

+

16

0.3+0.2

=0.05+0.02+0.03125=0.10125

% error =

R

P

ΔR

P

×100=0.10125×100=10.125%

Explanation:

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Answer 2

see the solved image answer .