Question

Two resistor having resistance of 12 ohm and 18 ohm are connected in series. If a potential difference of 2V is applied across them, calculate the current following through the circuit and the potential difference across each individual resistance.

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Answer 1

Explanation:

see, here the total resistance = r1 + r2 (as they are in series)

= 12 + 18 = 30 ohm

now, from V= IR

2V = I x 30ohm

I = 1/15 A

in a series, the current through the resistors remain the same, ie 1/15 A

now for 12 ohm resistor, we know that I = 1/15A, r = 12 ohm

from V = IR

v = 12 * 1/15 = 4/5 V

now for 18 ohm resistor, we know that I = 1/15A, r = 18 ohm

from V = IR

v = 18 * 1/15 = 6/5 V

hope it helped (please mark as brainliest if it did)

Answer 2

Explanation:

Explanation:

see, here the total resistance = r1 + r2 (as they are in series)

= 12 + 18 = 30 ohm

now, from V= IR

2V = I x 30ohm

I = 1/15 A

in a series, the current through the resistors remain the same, ie 1/15 A

now for 12 ohm resistor, we know that I = 1/15A, r = 12 ohm

from V = IR

v = 12 * 1/15 = 4/5 V

now for 18 ohm resistor, we know that I = 1/15A, r = 18 ohm

from V = IR

v = 18 * 1/15 = 6/5 V

hope it helped (please mark as brainliest if it did)