Two resistor of 10 and 15 are connected in series to a battery of 6 V . How can the values of current passing through them be compared?
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Heya,
These resistors are connected in series. And in series the current would be equally divided among each resistor. So,For the resistor of 10 ohm the current wud be V=IRI=V/RI=6/10I=6/15I= 0.6 A
Now the current for the second resistor would be,
V=IR
I=V/R
I=6/15I=0.4 ASo the current 0.6 A is larger than 0.4 A
If u like it u can make be as brainliest :)
These resistors are connected in series. And in series the current would be equally divided among each resistor. So,For the resistor of 10 ohm the current wud be V=IRI=V/RI=6/10I=6/15I= 0.6 A
Now the current for the second resistor would be,
V=IR
I=V/R
I=6/15I=0.4 ASo the current 0.6 A is larger than 0.4 A
If u like it u can make be as brainliest :)
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