Question

Two resistor of 10ohm and 15ohm are connected in series to a battery of 6v . How can the values of current passing through them be compared?

Answer 1

Since the resistors are connected in series total resistance will be
=> R=R1+R2
=> R=10+15=25 ohms

According to Ohm's law current 'I' flowing is directly proportional to the voltage 'V' and inversely proportional to the resistance 'R'.
[tex]=\ \textgreater \ I = \frac{V}{R} [/tex]
$I= \frac{6}{25} =.24 Amp$

Answer 2

Given:

• Resistances are 10 ohm and 15 ohm.
• Battery = 6V

To find:

• Current through the resistors?

Calculation:

First of all, the net resistance of the circuit is :

$R = R1 + R2$

$\implies \: R = 10 + 15$

$\implies \: R = 25 \: ohm$

Now, we know that :

• In series combination, the current passing through to all the resistances will be same. Instead the potential differences get divided among the resistances.

So, net current is :

$i = \dfrac{voltage}{R}$

$\implies \: i = \dfrac{6}{25}$

$\implies \: i = 0.24 \: ampere$

So, current through both 10 ohm and 15 ohm is 0.24 Amperes