two resistor of 20 ohm and 40 ohm are connected in parallel in an electic circit. how does this current passing through the two resistors compare?
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Solution:
Since the resistors are connected in parallel the potential Difference would be the same say V
Given that
R1=20 Ohm
R2=40 Ohm
Therefore, applying Ohm's law
I1=V/R1=V/20
I2=V/R2=V/40
Now
I1/I2=(V/20)/(V/40)=2
i.e. I1=2*I2
Clearly, the current through R1=20 Ohm will be twice that through R2=40 Ohm.
Since the resistors are connected in parallel the potential Difference would be the same say V
Given that
R1=20 Ohm
R2=40 Ohm
Therefore, applying Ohm's law
I1=V/R1=V/20
I2=V/R2=V/40
Now
I1/I2=(V/20)/(V/40)=2
i.e. I1=2*I2
Clearly, the current through R1=20 Ohm will be twice that through R2=40 Ohm.
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