two resistor of 6 ohm and 3 ohm are connected in parallel . Four such combinations are connected in series. calculate the equivalent resistance of combination thus formed .
Don't spam ××× only answer this question if you know the answer
Answers
Answered by
2
Explanation:
1/R = 1/6 + 1/3 (LCM = 6)
1/R = 1+2/6 = 3/6 = 6/3 = 2
Now four such combinations are connected in series ,
•°• Rs = 2+2+2+2 OR 2×4
= 8 ohm
Similar questions