Question

Two resistor of resistance 10 ohm and 20 ohm connected in parallel with potential diffrence of 12 v is applied across the combination.find the power cinsumed by each resister

Answer 1

R1=10 ohm
R2=20 ohm
R=(R1 xR2)/(R1+R2)
=(10 x 20)/(10+20)
=20/3 ohm

P=V²/R=(12*12)/(20/3)=(144*3)/20=21.6 watt

Answer 2

Answer:

4.8 watts

Explanation:

Given that 2 resistors of 10 ohm and 20 ohm are connected in series. 

Total resistance (R) = R₁+R₂ = 10+20 = 30Ω

Potential difference (V) = 12v

Power consumed (P) = ?

From ohms law, V = iR                           

i = V/R ----- 1

We know that, P = iV

From 1,          

P = V²/R

Placing the given values in the formula                       P = 12 x 12 / 30                     

 . P = 4.8 w

Therefore, Power consumed = 4.8 watts .