Question

Two resistor of resistance 10ohm and 20 ohm are joined in series A pottential diffrece pf 12 volt is applied across the combination find the power consumed by each resistor

Answer 1

r1=10ohms r2=20ohms
pd accross combination=12
power=v^2/r=12×12/10+20=12×12/30=4.8watts

Answer 2

Answer:

4.8 watts

Explanation:

Given that 2 resistors of 10 ohm and 20 ohm are connected in series. 

Total resistance (R) = R₁+R₂ = 10+20 = 30Ω

Potential difference (V) = 12v

Power consumed (P) = ?

From ohms law, V = iR                           

i = V/R ----- 1

We know that, P = iV

From 1,          

P = V²/R

Placing the given values in the formula                       P = 12 x 12 / 30                     

 . P = 4.8 w

Therefore, Power consumed = 4.8 watts .