two resistor of resistance of 10 ohms and 20 ohms are connected in parallel. A battery supplies a current of 6A to the combination. Calculate the current in each of the resistor and power of each resistor.
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The circuit current
I = 12/(10+20)
I = 12/30
I =0.4 Amps.
Power dissiparion in 10- ohm resistor
P1= I^2R1
P1 = 0.4 x0. 4 x10
P1= 1.6 watts
Power dissiparion in 20- ohm resistor
P2= I^2R2
P2 = 0.4 x0. 4 x20
P2= 3.2 watts
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